Base | Representation |
---|---|
bin | 11101101000100011010010… |
… | …101011101111100010100110 |
3 | 122002110102120100012210100012 |
4 | 131220203102223233202212 |
5 | 114040311341202441402 |
6 | 1141104441413250222 |
7 | 36311014310111624 |
oct | 3550432253574246 |
9 | 562412510183305 |
10 | 130330022312102 |
11 | 38588719997a08 |
12 | 1274a9b8933972 |
13 | 57950b728b7c2 |
14 | 24280146b6514 |
15 | 10102b27dc452 |
hex | 7688d2aef8a6 |
130330022312102 has 4 divisors (see below), whose sum is σ = 195495033468156. Its totient is φ = 65165011156050.
The previous prime is 130330022312101. The next prime is 130330022312107. The reversal of 130330022312102 is 201213220033031.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1303300223121023 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130330022312101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32582505578024 + ... + 32582505578027.
It is an arithmetic number, because the mean of its divisors is an integer number (48873758367039).
Almost surely, 2130330022312102 is an apocalyptic number.
130330022312102 is a deficient number, since it is larger than the sum of its proper divisors (65165011156054).
130330022312102 is an equidigital number, since it uses as much as digits as its factorization.
130330022312102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65165011156053.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 130330022312102 its reverse (201213220033031), we get a palindrome (331543242345133).
The spelling of 130330022312102 in words is "one hundred thirty trillion, three hundred thirty billion, twenty-two million, three hundred twelve thousand, one hundred two".
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