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130330022312102 = 265165011156051
BaseRepresentation
bin11101101000100011010010…
…101011101111100010100110
3122002110102120100012210100012
4131220203102223233202212
5114040311341202441402
61141104441413250222
736311014310111624
oct3550432253574246
9562412510183305
10130330022312102
1138588719997a08
121274a9b8933972
1357950b728b7c2
1424280146b6514
1510102b27dc452
hex7688d2aef8a6

130330022312102 has 4 divisors (see below), whose sum is σ = 195495033468156. Its totient is φ = 65165011156050.

The previous prime is 130330022312101. The next prime is 130330022312107. The reversal of 130330022312102 is 201213220033031.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1303300223121023 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130330022312101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32582505578024 + ... + 32582505578027.

It is an arithmetic number, because the mean of its divisors is an integer number (48873758367039).

Almost surely, 2130330022312102 is an apocalyptic number.

130330022312102 is a deficient number, since it is larger than the sum of its proper divisors (65165011156054).

130330022312102 is an equidigital number, since it uses as much as digits as its factorization.

130330022312102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65165011156053.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130330022312102 its reverse (201213220033031), we get a palindrome (331543242345133).

The spelling of 130330022312102 in words is "one hundred thirty trillion, three hundred thirty billion, twenty-two million, three hundred twelve thousand, one hundred two".

Divisors: 1 2 65165011156051 130330022312102