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130330113012173 is a prime number
BaseRepresentation
bin11101101000100011011000…
…000101101111000111001101
3122002110102210122212211110002
4131220203120011233013031
5114040312032412342143
61141104454413254045
736311016461051414
oct3550433005570715
9562412718784402
10130330113012173
1138588766107248
121274aa23194325
1357950cccc7299
14242802276647b
1510102ba7565b8
hex7688d816f1cd

130330113012173 has 2 divisors, whose sum is σ = 130330113012174. Its totient is φ = 130330113012172.

The previous prime is 130330113012167. The next prime is 130330113012251. The reversal of 130330113012173 is 371210311033031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84736112069284 + 45594000942889 = 9205222^2 + 6752333^2 .

It is an emirp because it is prime and its reverse (371210311033031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130330113012173 - 24 = 130330113012157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130330113012163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165056506086 + 65165056506087.

It is an arithmetic number, because the mean of its divisors is an integer number (65165056506087).

Almost surely, 2130330113012173 is an apocalyptic number.

It is an amenable number.

130330113012173 is a deficient number, since it is larger than the sum of its proper divisors (1).

130330113012173 is an equidigital number, since it uses as much as digits as its factorization.

130330113012173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 29.

The spelling of 130330113012173 in words is "one hundred thirty trillion, three hundred thirty billion, one hundred thirteen million, twelve thousand, one hundred seventy-three".