Base | Representation |
---|---|
bin | 11101101000100011011101… |
… | …011101000011110000010001 |
3 | 122002110110000221020022011012 |
4 | 131220203131131003300101 |
5 | 114040312223432341423 |
6 | 1141104511350300305 |
7 | 36311021633044046 |
oct | 3550433535036021 |
9 | 562413027208135 |
10 | 130330203012113 |
11 | 38588801998565 |
12 | 1274aa49357695 |
13 | 57951158491a0 |
14 | 24280306b31cd |
15 | 10102c35d3078 |
hex | 7688dd743c11 |
130330203012113 has 4 divisors (see below), whose sum is σ = 140355603243828. Its totient is φ = 120304802780400.
The previous prime is 130330203012059. The next prime is 130330203012131. The reversal of 130330203012113 is 311210302033031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 69169544813329 + 61160658198784 = 8316823^2 + 7820528^2 .
It is a cyclic number.
It is not a de Polignac number, because 130330203012113 - 26 = 130330203012049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130330203012133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5012700115838 + ... + 5012700115863.
It is an arithmetic number, because the mean of its divisors is an integer number (35088900810957).
Almost surely, 2130330203012113 is an apocalyptic number.
130330203012113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
130330203012113 is a deficient number, since it is larger than the sum of its proper divisors (10025400231715).
130330203012113 is a wasteful number, since it uses less digits than its factorization.
130330203012113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10025400231714.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 130330203012113 its reverse (311210302033031), we get a palindrome (441540505045144).
The spelling of 130330203012113 in words is "one hundred thirty trillion, three hundred thirty billion, two hundred three million, twelve thousand, one hundred thirteen".
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