Base | Representation |
---|---|
bin | 1011110110101000101001… |
… | …0000110010100001001100 |
3 | 1201010222002122001112121201 |
4 | 2331222022100302201030 |
5 | 3202014044102324400 |
6 | 43415220444435244 |
7 | 2513423044540522 |
oct | 275521220624114 |
9 | 51128078045551 |
10 | 13033250433100 |
11 | 4175409103277 |
12 | 1565b21248b24 |
13 | 7370515995c1 |
14 | 330b54026312 |
15 | 17905882206a |
hex | bda8a43284c |
13033250433100 has 36 divisors (see below), whose sum is σ = 28292790404200. Its totient is φ = 5211339442560.
The previous prime is 13033250433097. The next prime is 13033250433173. The reversal of 13033250433100 is 133405233031.
It is a super-2 number, since 2×130332504331002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24241905 + ... + 24773704.
Almost surely, 213033250433100 is an apocalyptic number.
13033250433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13033250433100 is an abundant number, since it is smaller than the sum of its proper divisors (15259539971100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13033250433100 is a wasteful number, since it uses less digits than its factorization.
13033250433100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49018282 (or 49018275 counting only the distinct ones).
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 13033250433100 its reverse (133405233031), we get a palindrome (13166655666131).
The spelling of 13033250433100 in words is "thirteen trillion, thirty-three billion, two hundred fifty million, four hundred thirty-three thousand, one hundred".
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