Base | Representation |
---|---|
bin | 111100101100101110… |
… | …1110101101011000001 |
3 | 110110110022112202100202 |
4 | 1321121131311223001 |
5 | 4113424100404441 |
6 | 135514301054545 |
7 | 12263123554526 |
oct | 1713135655301 |
9 | 413408482322 |
10 | 130350013121 |
11 | 50310203179 |
12 | 21319b57455 |
13 | c3a45639a3 |
14 | 6447b7b14d |
15 | 35cd95119b |
hex | 1e59775ac1 |
130350013121 has 8 divisors (see below), whose sum is σ = 133975521000. Its totient is φ = 126772525440.
The previous prime is 130350013103. The next prime is 130350013139. The reversal of 130350013121 is 121310053031.
It is an interprime number because it is at equal distance from previous prime (130350013103) and next prime (130350013139).
It can be written as a sum of positive squares in 4 ways, for example, as 12385241521 + 117964771600 = 111289^2 + 343460^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130350013121 - 222 = 130345818817 is a prime.
It is a super-2 number, since 2×1303500131212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130350013093 and 130350013102.
It is not an unprimeable number, because it can be changed into a prime (130350013151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11999546 + ... + 12010403.
It is an arithmetic number, because the mean of its divisors is an integer number (16746940125).
Almost surely, 2130350013121 is an apocalyptic number.
It is an amenable number.
130350013121 is a deficient number, since it is larger than the sum of its proper divisors (3625507879).
130350013121 is an equidigital number, since it uses as much as digits as its factorization.
130350013121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24010099.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 130350013121 its reverse (121310053031), we get a palindrome (251660066152).
The spelling of 130350013121 in words is "one hundred thirty billion, three hundred fifty million, thirteen thousand, one hundred twenty-one".
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