Base | Representation |
---|---|
bin | 111100101100101110… |
… | …1110101101111100101 |
3 | 110110110022112202202120 |
4 | 1321121131311233211 |
5 | 4113424100412123 |
6 | 135514301100153 |
7 | 12263123555424 |
oct | 1713135655745 |
9 | 413408482676 |
10 | 130350013413 |
11 | 50310203414 |
12 | 21319b57659 |
13 | c3a4563b69 |
14 | 6447b7b2bb |
15 | 35cd9512e3 |
hex | 1e59775be5 |
130350013413 has 8 divisors (see below), whose sum is σ = 173840996448. Its totient is φ = 86879519664.
The previous prime is 130350013403. The next prime is 130350013429. The reversal of 130350013413 is 314310053031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130350013413 - 29 = 130350012901 is a prime.
It is a super-2 number, since 2×1303500134132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130350013403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5107470 + ... + 5132927.
It is an arithmetic number, because the mean of its divisors is an integer number (21730124556).
Almost surely, 2130350013413 is an apocalyptic number.
It is an amenable number.
130350013413 is a deficient number, since it is larger than the sum of its proper divisors (43490983035).
130350013413 is a wasteful number, since it uses less digits than its factorization.
130350013413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10244643.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 130350013413 its reverse (314310053031), we get a palindrome (444660066444).
The spelling of 130350013413 in words is "one hundred thirty billion, three hundred fifty million, thirteen thousand, four hundred thirteen".
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