13035403221 has 4 divisors (see below), whose sum is σ = 17380537632. Its totient is φ = 8690268812.

The previous prime is 13035403211. The next prime is 13035403231. The reversal of 13035403221 is 12230453031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12230453031 = 3 ⋅4076817677.

It is an interprime number because it is at equal distance from previous prime (13035403211) and next prime (13035403231).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13035403221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13035403191 and 13035403200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13035403211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2172567201 + ... + 2172567206.

It is an arithmetic number, because the mean of its divisors is an integer number (4345134408).

Almost surely, 2^13035403221 is an apocalyptic number.

It is an amenable number.

13035403221 is a deficient number, since it is larger than the sum of its proper divisors (4345134411).

13035403221 is an equidigital number, since it uses as much as digits as its factorization.

13035403221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4345134410.

The product of its (nonzero) digits is 2160, while the sum is 24.

Adding to 13035403221 its reverse (12230453031), we get a palindrome (25265856252).

The spelling of 13035403221 in words is "thirteen billion, thirty-five million, four hundred three thousand, two hundred twenty-one".