13040013010433 has 4 divisors (see below), whose sum is σ = 13807072599300. Its totient is φ = 12272953421568.

The previous prime is 13040013010391. The next prime is 13040013010441. The reversal of 13040013010433 is 33401031004031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7776329000449 + 5263684009984 = 2788607^2 + 2294272^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040013010433 - 2²⁶ = 13039945901569 is a prime.

It is a super-2 number, since 2×13040013010433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040013010399 and 13040013010408.

It is not an unprimeable number, because it can be changed into a prime (13040013040433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383529794408 + ... + 383529794441.

It is an arithmetic number, because the mean of its divisors is an integer number (3451768149825).

Almost surely, 2^{13040013010433} is an apocalyptic number.

It is an amenable number.

13040013010433 is a deficient number, since it is larger than the sum of its proper divisors (767059588867).

13040013010433 is an equidigital number, since it uses as much as digits as its factorization.

13040013010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 767059588866.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13040013010433 its reverse (33401031004031), we get a palindrome (46441044014464).

The spelling of 13040013010433 in words is "thirteen trillion, forty billion, thirteen million, ten thousand, four hundred thirty-three".