Base | Representation |
---|---|
bin | 11000010010011111… |
… | …01110111010011011 |
3 | 1020122210002201011012 |
4 | 30021033232322123 |
5 | 203201221134042 |
6 | 5553540524135 |
7 | 641100231236 |
oct | 141117567233 |
9 | 36583081135 |
10 | 13040021147 |
11 | 559182a98a |
12 | 263b0b064b |
13 | 12ca77505a |
14 | 8b9bc641d |
15 | 514c09e82 |
hex | 3093eee9b |
13040021147 has 2 divisors, whose sum is σ = 13040021148. Its totient is φ = 13040021146.
The previous prime is 13040021123. The next prime is 13040021191. The reversal of 13040021147 is 74112004031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13040021147 - 26 = 13040021083 is a prime.
It is not a weakly prime, because it can be changed into another prime (13040021107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520010573 + 6520010574.
It is an arithmetic number, because the mean of its divisors is an integer number (6520010574).
Almost surely, 213040021147 is an apocalyptic number.
13040021147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040021147 is an equidigital number, since it uses as much as digits as its factorization.
13040021147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 13040021147 its reverse (74112004031), we get a palindrome (87152025178).
The spelling of 13040021147 in words is "thirteen billion, forty million, twenty-one thousand, one hundred forty-seven".
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