130401211 has 2 divisors, whose sum is σ = 130401212. Its totient is φ = 130401210.

The previous prime is 130401179. The next prime is 130401251. The reversal of 130401211 is 112104031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130401211 - 2⁵ = 130401179 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130401191 and 130401200.

It is not a weakly prime, because it can be changed into another prime (130401251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200605 + 65200606.

It is an arithmetic number, because the mean of its divisors is an integer number (65200606).

Almost surely, 2^130401211 is an apocalyptic number.

130401211 is a deficient number, since it is larger than the sum of its proper divisors (1).

130401211 is an equidigital number, since it uses as much as digits as its factorization.

130401211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 130401211 is about 11419.3349631229. The cubic root of 130401211 is about 507.1003086246.

Adding to 130401211 its reverse (112104031), we get a palindrome (242505242).

The spelling of 130401211 in words is "one hundred thirty million, four hundred one thousand, two hundred eleven".