Base | Representation |
---|---|
bin | 111100101110010010… |
… | …1011000111010001101 |
3 | 110110120221222102112202 |
4 | 1321130211120322031 |
5 | 4114030443332414 |
6 | 135523410211245 |
7 | 12264330315641 |
oct | 1713445307215 |
9 | 413527872482 |
10 | 130402324109 |
11 | 503377921a2 |
12 | 21333583b25 |
13 | c3b234ac35 |
14 | 6450ab6c21 |
15 | 35d33359de |
hex | 1e5c958e8d |
130402324109 has 2 divisors, whose sum is σ = 130402324110. Its totient is φ = 130402324108.
The previous prime is 130402324103. The next prime is 130402324121. The reversal of 130402324109 is 901423204031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97415773225 + 32986550884 = 312115^2 + 181622^2 .
It is a cyclic number.
It is not a de Polignac number, because 130402324109 - 24 = 130402324093 is a prime.
It is a super-2 number, since 2×1304023241092 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130402324103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201162054 + 65201162055.
It is an arithmetic number, because the mean of its divisors is an integer number (65201162055).
Almost surely, 2130402324109 is an apocalyptic number.
It is an amenable number.
130402324109 is a deficient number, since it is larger than the sum of its proper divisors (1).
130402324109 is an equidigital number, since it uses as much as digits as its factorization.
130402324109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 130402324109 in words is "one hundred thirty billion, four hundred two million, three hundred twenty-four thousand, one hundred nine".
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