Base | Representation |
---|---|
bin | 111100101110010010… |
… | …1011000111010000111 |
3 | 110110120221222102112112 |
4 | 1321130211120322013 |
5 | 4114030443332403 |
6 | 135523410211235 |
7 | 12264330315632 |
oct | 1713445307207 |
9 | 413527872475 |
10 | 130402324103 |
11 | 50337792197 |
12 | 21333583b1b |
13 | c3b234ac2c |
14 | 6450ab6c19 |
15 | 35d33359d8 |
hex | 1e5c958e87 |
130402324103 has 2 divisors, whose sum is σ = 130402324104. Its totient is φ = 130402324102.
The previous prime is 130402324093. The next prime is 130402324109. The reversal of 130402324103 is 301423204031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130402324103 - 220 = 130401275527 is a prime.
It is a super-2 number, since 2×1304023241032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130402324109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201162051 + 65201162052.
It is an arithmetic number, because the mean of its divisors is an integer number (65201162052).
Almost surely, 2130402324103 is an apocalyptic number.
130402324103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130402324103 is an equidigital number, since it uses as much as digits as its factorization.
130402324103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130402324103 its reverse (301423204031), we get a palindrome (431825528134).
The spelling of 130402324103 in words is "one hundred thirty billion, four hundred two million, three hundred twenty-four thousand, one hundred three".
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