Base | Representation |
---|---|
bin | 11000010010100001… |
… | …00101000110101010 |
3 | 1020122210111222122012 |
4 | 30021100211012222 |
5 | 203201300234424 |
6 | 5553545355522 |
7 | 641102144333 |
oct | 141120450652 |
9 | 36583458565 |
10 | 13040243114 |
11 | 5591971728 |
12 | 263b198ba2 |
13 | 12ca8220b2 |
14 | 8b9c4328a |
15 | 514c50b0e |
hex | 3094251aa |
13040243114 has 4 divisors (see below), whose sum is σ = 19560364674. Its totient is φ = 6520121556.
The previous prime is 13040243101. The next prime is 13040243131. The reversal of 13040243114 is 41134204031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12990300625 + 49942489 = 113975^2 + 7067^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13040243114.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3260060777 + ... + 3260060780.
Almost surely, 213040243114 is an apocalyptic number.
13040243114 is a deficient number, since it is larger than the sum of its proper divisors (6520121560).
13040243114 is an equidigital number, since it uses as much as digits as its factorization.
13040243114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6520121559.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13040243114 its reverse (41134204031), we get a palindrome (54174447145).
The spelling of 13040243114 in words is "thirteen billion, forty million, two hundred forty-three thousand, one hundred fourteen".
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