Base | Representation |
---|---|
bin | 1011110111000010111010… |
… | …1001011001000110101011 |
3 | 1201011122022011021222102202 |
4 | 2331300232221121012223 |
5 | 3202123020122011243 |
6 | 43422344352250415 |
7 | 2514062605201526 |
oct | 275605651310653 |
9 | 51148264258382 |
10 | 13040303313323 |
11 | 41783a8295600 |
12 | 156736b240a0b |
13 | 737906828900 |
14 | 3312229c9bbd |
15 | 17931cad44b8 |
hex | bdc2ea591ab |
13040303313323 has 72 divisors (see below), whose sum is σ = 15620810700096. Its totient is φ = 10872655073280.
The previous prime is 13040303313319. The next prime is 13040303313451. The reversal of 13040303313323 is 32331330304031.
It is not a de Polignac number, because 13040303313323 - 22 = 13040303313319 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13040303315323) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 4313694590 + ... + 4313697612.
It is an arithmetic number, because the mean of its divisors is an integer number (216955704168).
Almost surely, 213040303313323 is an apocalyptic number.
13040303313323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13040303313323 is a deficient number, since it is larger than the sum of its proper divisors (2580507386773).
13040303313323 is a wasteful number, since it uses less digits than its factorization.
13040303313323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4357 (or 4333 counting only the distinct ones).
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 13040303313323 its reverse (32331330304031), we get a palindrome (45371633617354).
The spelling of 13040303313323 in words is "thirteen trillion, forty billion, three hundred three million, three hundred thirteen thousand, three hundred twenty-three".
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