13040311 has 4 divisors (see below), whose sum is σ = 13096512. Its totient is φ = 12984112.

The previous prime is 13040297. The next prime is 13040323. The reversal of 13040311 is 11304031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13040311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040291 and 13040300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27751 + ... + 28216.

It is an arithmetic number, because the mean of its divisors is an integer number (3274128).

Almost surely, 2^13040311 is an apocalyptic number.

13040311 is a deficient number, since it is larger than the sum of its proper divisors (56201).

13040311 is an equidigital number, since it uses as much as digits as its factorization.

13040311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56200.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 13040311 is about 3611.1370785391. The cubic root of 13040311 is about 235.3762555673.

Adding to 13040311 its reverse (11304031), we get a palindrome (24344342).

The spelling of 13040311 in words is "thirteen million, forty thousand, three hundred eleven".