1304040131101 has 4 divisors (see below), whose sum is σ = 1304081394592. Its totient is φ = 1303998867612.

The previous prime is 1304040131099. The next prime is 1304040131129. The reversal of 1304040131101 is 1011310404031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304040131101 - 2¹ = 1304040131099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304040131171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20584305 + ... + 20647558.

It is an arithmetic number, because the mean of its divisors is an integer number (326020348648).

Almost surely, 2^{1304040131101} is an apocalyptic number.

It is an amenable number.

1304040131101 is a deficient number, since it is larger than the sum of its proper divisors (41263491).

1304040131101 is an equidigital number, since it uses as much as digits as its factorization.

1304040131101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41263490.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1304040131101 its reverse (1011310404031), we get a palindrome (2315350535132).

The spelling of 1304040131101 in words is "one trillion, three hundred four billion, forty million, one hundred thirty-one thousand, one hundred one".