13040411551 has 4 divisors (see below), whose sum is σ = 13045110192. Its totient is φ = 13035712912.

The previous prime is 13040411539. The next prime is 13040411567. The reversal of 13040411551 is 15511404031.

13040411551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13040411551 - 2¹⁵ = 13040378783 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040418551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2345155 + ... + 2350708.

It is an arithmetic number, because the mean of its divisors is an integer number (3261277548).

Almost surely, 2^13040411551 is an apocalyptic number.

13040411551 is a deficient number, since it is larger than the sum of its proper divisors (4698641).

13040411551 is an equidigital number, since it uses as much as digits as its factorization.

13040411551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4698640.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 13040411551 its reverse (15511404031), we get a palindrome (28551815582).

The spelling of 13040411551 in words is "thirteen billion, forty million, four hundred eleven thousand, five hundred fifty-one".