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13040498039 is a prime number
BaseRepresentation
bin11000010010100011…
…00011010101110111
31020122210222221022212
430021101203111313
5203201331414124
65553555044035
7641104255502
oct141121432567
936583887285
1013040498039
115592026208
12263b2a061b
1312ca8b113a
148b9cac139
15514ca140e
hex309463577

13040498039 has 2 divisors, whose sum is σ = 13040498040. Its totient is φ = 13040498038.

The previous prime is 13040498017. The next prime is 13040498111. The reversal of 13040498039 is 93089404031.

13040498039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13040498039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13040497987 and 13040498005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040498239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520249019 + 6520249020.

It is an arithmetic number, because the mean of its divisors is an integer number (6520249020).

Almost surely, 213040498039 is an apocalyptic number.

13040498039 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040498039 is an equidigital number, since it uses as much as digits as its factorization.

13040498039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 13040498039 in words is "thirteen billion, forty million, four hundred ninety-eight thousand, thirty-nine".