1304054431 has 2 divisors, whose sum is σ = 1304054432. Its totient is φ = 1304054430.

The previous prime is 1304054429. The next prime is 1304054441. The reversal of 1304054431 is 1344504031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1304054431 - 2¹ = 1304054429 is a prime.

It is a super-2 number, since 2×1304054431² = 3401115918021467522, which contains 22 as substring.

Together with 1304054429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1304054396 and 1304054405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304054441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652027215 + 652027216.

It is an arithmetic number, because the mean of its divisors is an integer number (652027216).

Almost surely, 2^1304054431 is an apocalyptic number.

1304054431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304054431 is an equidigital number, since it uses as much as digits as its factorization.

1304054431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1304054431 is about 36111.6938262386. The cubic root of 1304054431 is about 1092.5263150858.

Adding to 1304054431 its reverse (1344504031), we get a palindrome (2648558462).

Subtracting 1304054431 from its reverse (1344504031), we obtain a square (40449600 = 6360²).

The spelling of 1304054431 in words is "one billion, three hundred four million, fifty-four thousand, four hundred thirty-one".