Base | Representation |
---|---|
bin | 111100101110100011… |
… | …0111101100110100101 |
3 | 110110121120112120022111 |
4 | 1321131012331212211 |
5 | 4114040222001112 |
6 | 135524323001021 |
7 | 12264465162655 |
oct | 1713506754645 |
9 | 413546476274 |
10 | 130411125157 |
11 | 50341753595 |
12 | 21336509171 |
13 | c3b410cb61 |
14 | 6451d28365 |
15 | 35d3ec35a7 |
hex | 1e5d1bd9a5 |
130411125157 has 2 divisors, whose sum is σ = 130411125158. Its totient is φ = 130411125156.
The previous prime is 130411125139. The next prime is 130411125167. The reversal of 130411125157 is 751521114031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124647126916 + 5763998241 = 353054^2 + 75921^2 .
It is a cyclic number.
It is not a de Polignac number, because 130411125157 - 219 = 130410600869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130411125167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205562578 + 65205562579.
It is an arithmetic number, because the mean of its divisors is an integer number (65205562579).
Almost surely, 2130411125157 is an apocalyptic number.
It is an amenable number.
130411125157 is a deficient number, since it is larger than the sum of its proper divisors (1).
130411125157 is an equidigital number, since it uses as much as digits as its factorization.
130411125157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 31.
Adding to 130411125157 its reverse (751521114031), we get a palindrome (881932239188).
The spelling of 130411125157 in words is "one hundred thirty billion, four hundred eleven million, one hundred twenty-five thousand, one hundred fifty-seven".
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