Base | Representation |
---|---|
bin | 11101101001101111000111… |
… | …001100101110010110000111 |
3 | 122002202012201001200112210011 |
4 | 131221233013030232112013 |
5 | 114043130104101304431 |
6 | 1141210104040411051 |
7 | 36316625623116541 |
oct | 3551570714562607 |
9 | 562665631615704 |
10 | 130411434009991 |
11 | 3860a1a6752562 |
12 | 12762739476a87 |
13 | 579c98ca096c4 |
14 | 242bd38b2a691 |
15 | 1012479bb1cb1 |
hex | 769bc732e587 |
130411434009991 has 2 divisors, whose sum is σ = 130411434009992. Its totient is φ = 130411434009990.
The previous prime is 130411434009811. The next prime is 130411434010009. The reversal of 130411434009991 is 199900434114031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130411434009991 - 213 = 130411434001799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130411434019991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205717004995 + 65205717004996.
It is an arithmetic number, because the mean of its divisors is an integer number (65205717004996).
Almost surely, 2130411434009991 is an apocalyptic number.
130411434009991 is a deficient number, since it is larger than the sum of its proper divisors (1).
130411434009991 is an equidigital number, since it uses as much as digits as its factorization.
130411434009991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 419904, while the sum is 49.
The spelling of 130411434009991 in words is "one hundred thirty trillion, four hundred eleven billion, four hundred thirty-four million, nine thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •