Base | Representation |
---|---|
bin | 1011110111000110010010… |
… | …1100001000101110000111 |
3 | 1201011201122100101112220101 |
4 | 2331301210230020232013 |
5 | 3202131344230033221 |
6 | 43423014341544531 |
7 | 2514124225006621 |
oct | 275614454105607 |
9 | 51151570345811 |
10 | 13041210002311 |
11 | 4178823076447 |
12 | 1567582a15147 |
13 | 737a1c624a7a |
14 | 3312ab1a7c11 |
15 | 1793724d2d91 |
hex | bdc64b08b87 |
13041210002311 has 4 divisors (see below), whose sum is σ = 13041334594800. Its totient is φ = 13041085409824.
The previous prime is 13041210002291. The next prime is 13041210002323. The reversal of 13041210002311 is 11320001214031.
13041210002311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13041210002311 - 211 = 13041210000263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13041210002011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62139106 + ... + 62348623.
It is an arithmetic number, because the mean of its divisors is an integer number (3260333648700).
Almost surely, 213041210002311 is an apocalyptic number.
13041210002311 is a deficient number, since it is larger than the sum of its proper divisors (124592489).
13041210002311 is a wasteful number, since it uses less digits than its factorization.
13041210002311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124592488.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13041210002311 its reverse (11320001214031), we get a palindrome (24361211216342).
The spelling of 13041210002311 in words is "thirteen trillion, forty-one billion, two hundred ten million, two thousand, three hundred eleven".
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