Base | Representation |
---|---|
bin | 11000010010101001… |
… | …01001001000001011 |
3 | 1020122212112002121202 |
4 | 30021110221020023 |
5 | 203202033330141 |
6 | 5554024254415 |
7 | 641114201423 |
oct | 141124511013 |
9 | 36585462552 |
10 | 13041308171 |
11 | 5592529941 |
12 | 263b61140b |
13 | 12cab05ac8 |
14 | 8ba03d483 |
15 | 514db149b |
hex | 30952920b |
13041308171 has 2 divisors, whose sum is σ = 13041308172. Its totient is φ = 13041308170.
The previous prime is 13041308113. The next prime is 13041308183. The reversal of 13041308171 is 17180314031.
It is a strong prime.
It is an emirp because it is prime and its reverse (17180314031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13041308171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13041305171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520654085 + 6520654086.
It is an arithmetic number, because the mean of its divisors is an integer number (6520654086).
Almost surely, 213041308171 is an apocalyptic number.
13041308171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13041308171 is an equidigital number, since it uses as much as digits as its factorization.
13041308171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 13041308171 in words is "thirteen billion, forty-one million, three hundred eight thousand, one hundred seventy-one".
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