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130413140111 = 177671361183
BaseRepresentation
bin111100101110100111…
…0101001100010001111
3110110121201022221022102
41321131032221202033
54114041230440421
6135524434105315
712264521254322
oct1713516514217
9413551287272
10130413140111
11503428aa441
122133711b23b
13c3b4667037
1464522d07b9
1535d427060b
hex1e5d3a988f

130413140111 has 4 divisors (see below), whose sum is σ = 138084501312. Its totient is φ = 122741778912.

The previous prime is 130413140107. The next prime is 130413140149. The reversal of 130413140111 is 111041314031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130413140111 - 22 = 130413140107 is a prime.

It is a super-2 number, since 2×1304131401112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130413140411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3835680575 + ... + 3835680608.

It is an arithmetic number, because the mean of its divisors is an integer number (34521125328).

Almost surely, 2130413140111 is an apocalyptic number.

130413140111 is a deficient number, since it is larger than the sum of its proper divisors (7671361201).

130413140111 is an equidigital number, since it uses as much as digits as its factorization.

130413140111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7671361200.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 130413140111 its reverse (111041314031), we get a palindrome (241454454142).

The spelling of 130413140111 in words is "one hundred thirty billion, four hundred thirteen million, one hundred forty thousand, one hundred eleven".

Divisors: 1 17 7671361183 130413140111