Base | Representation |
---|---|
bin | 111100101110110100… |
… | …1101011010010110111 |
3 | 110110122012122220020101 |
4 | 1321131221223102313 |
5 | 4114100034201312 |
6 | 135525250014531 |
7 | 12264635423506 |
oct | 1713551532267 |
9 | 413565586211 |
10 | 130420225207 |
11 | 503468a9598 |
12 | 21339577447 |
13 | c3b5c77bbc |
14 | 645321683d |
15 | 35d4bbea57 |
hex | 1e5da6b4b7 |
130420225207 has 2 divisors, whose sum is σ = 130420225208. Its totient is φ = 130420225206.
The previous prime is 130420225181. The next prime is 130420225249. The reversal of 130420225207 is 702522024031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130420225207 - 211 = 130420223159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130420225267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65210112603 + 65210112604.
It is an arithmetic number, because the mean of its divisors is an integer number (65210112604).
Almost surely, 2130420225207 is an apocalyptic number.
130420225207 is a deficient number, since it is larger than the sum of its proper divisors (1).
130420225207 is an equidigital number, since it uses as much as digits as its factorization.
130420225207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 28.
Adding to 130420225207 its reverse (702522024031), we get a palindrome (832942249238).
It can be divided in two parts, 1304202 and 25207, that added together give a square (1329409 = 11532).
The spelling of 130420225207 in words is "one hundred thirty billion, four hundred twenty million, two hundred twenty-five thousand, two hundred seven".
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