13042112333 has 4 divisors (see below), whose sum is σ = 13225804128. Its totient is φ = 12858420540.

The previous prime is 13042112311. The next prime is 13042112339. The reversal of 13042112333 is 33321124031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13042112333 - 2¹² = 13042108237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13042112299 and 13042112308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13042112339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91845791 + ... + 91845932.

It is an arithmetic number, because the mean of its divisors is an integer number (3306451032).

Almost surely, 2^13042112333 is an apocalyptic number.

It is an amenable number.

13042112333 is a deficient number, since it is larger than the sum of its proper divisors (183691795).

13042112333 is an equidigital number, since it uses as much as digits as its factorization.

13042112333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183691794.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13042112333 its reverse (33321124031), we get a palindrome (46363236364).

The spelling of 13042112333 in words is "thirteen billion, forty-two million, one hundred twelve thousand, three hundred thirty-three".