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13042321341241 is a prime number
BaseRepresentation
bin1011110111001010011011…
…1011100011101100111001
31201011211111210120102022111
42331302212323203230321
53202141133230404431
643423320521452321
72514163611150043
oct275624673435471
951154453512274
1013042321341241
114179243425875
1215678330410a1
13737b6894587a
14331374a18a93
151793d9d587b1
hexbdca6ee3b39

13042321341241 has 2 divisors, whose sum is σ = 13042321341242. Its totient is φ = 13042321341240.

The previous prime is 13042321341239. The next prime is 13042321341271. The reversal of 13042321341241 is 14214312324031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12316562174016 + 725759167225 = 3509496^2 + 851915^2 .

It is a cyclic number.

It is not a de Polignac number, because 13042321341241 - 21 = 13042321341239 is a prime.

Together with 13042321341239, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13042321341211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521160670620 + 6521160670621.

It is an arithmetic number, because the mean of its divisors is an integer number (6521160670621).

Almost surely, 213042321341241 is an apocalyptic number.

It is an amenable number.

13042321341241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13042321341241 is an equidigital number, since it uses as much as digits as its factorization.

13042321341241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13042321341241 its reverse (14214312324031), we get a palindrome (27256633665272).

The spelling of 13042321341241 in words is "thirteen trillion, forty-two billion, three hundred twenty-one million, three hundred forty-one thousand, two hundred forty-one".