Base | Representation |
---|---|
bin | 10010111110101010110… |
… | …010101010111100000111 |
3 | 11121200110202121012022202 |
4 | 102332222302222330013 |
5 | 132332041032003422 |
6 | 2435054304145115 |
7 | 163141203223511 |
oct | 22765262527407 |
9 | 4550422535282 |
10 | 1304240500487 |
11 | 463141840a51 |
12 | 19092b60819b |
13 | 95cb27b3722 |
14 | 471a8824bb1 |
15 | 23dd6354b92 |
hex | 12faacaaf07 |
1304240500487 has 2 divisors, whose sum is σ = 1304240500488. Its totient is φ = 1304240500486.
The previous prime is 1304240500421. The next prime is 1304240500499. The reversal of 1304240500487 is 7840050424031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304240500487 is a prime.
It is a super-2 number, since 2×13042405004872 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1304240500487.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304240503487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120250243 + 652120250244.
It is an arithmetic number, because the mean of its divisors is an integer number (652120250244).
Almost surely, 21304240500487 is an apocalyptic number.
1304240500487 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304240500487 is an equidigital number, since it uses as much as digits as its factorization.
1304240500487 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 107520, while the sum is 38.
The spelling of 1304240500487 in words is "one trillion, three hundred four billion, two hundred forty million, five hundred thousand, four hundred eighty-seven".
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