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1304242543112 = 23193844716673
BaseRepresentation
bin10010111110101010111…
…010011101101000001000
311121200110220102222021112
4102332222322131220020
5132332042042334422
62435054420025452
7163141226461625
oct22765272355010
94550426388245
101304242543112
11463142a06673
12190930232288
1395cb304a392
14471a8bd734c
1523dd6609ee2
hex12faae9da08

1304242543112 has 16 divisors (see below), whose sum is σ = 2458125521340. Its totient is φ = 648742404096.

The previous prime is 1304242543099. The next prime is 1304242543129. The reversal of 1304242543112 is 2113452424031.

It can be written as a sum of positive squares in 2 ways, for example, as 1285334643076 + 18907900036 = 1133726^2 + 137506^2 .

It is a super-3 number, since 3×13042425431123 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 422356793 + ... + 422359880.

Almost surely, 21304242543112 is an apocalyptic number.

It is an amenable number.

1304242543112 is a deficient number, since it is larger than the sum of its proper divisors (1153882978228).

1304242543112 is a wasteful number, since it uses less digits than its factorization.

1304242543112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 844716872 (or 844716868 counting only the distinct ones).

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1304242543112 its reverse (2113452424031), we get a palindrome (3417694967143).

The spelling of 1304242543112 in words is "one trillion, three hundred four billion, two hundred forty-two million, five hundred forty-three thousand, one hundred twelve".

Divisors: 1 2 4 8 193 386 772 1544 844716673 1689433346 3378866692 6757733384 163030317889 326060635778 652121271556 1304242543112