Base | Representation |
---|---|
bin | 10010111110101010111… |
… | …100101000110010101111 |
3 | 11121200110221111221012111 |
4 | 102332222330220302233 |
5 | 132332042214110020 |
6 | 2435054440144451 |
7 | 163141234354534 |
oct | 22765274506257 |
9 | 4550427457174 |
10 | 1304243113135 |
11 | 463143265966 |
12 | 190930468127 |
13 | 95cb31b9981 |
14 | 471a8d04d8b |
15 | 23dd66bdd5a |
hex | 12faaf28caf |
1304243113135 has 8 divisors (see below), whose sum is σ = 1567510737696. Its totient is φ = 1041781822560.
The previous prime is 1304243113133. The next prime is 1304243113139. The reversal of 1304243113135 is 5313113424031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1304243113135 - 21 = 1304243113133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1304243113097 and 1304243113106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304243113133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201579936 + ... + 201586405.
It is an arithmetic number, because the mean of its divisors is an integer number (195938842212).
Almost surely, 21304243113135 is an apocalyptic number.
1304243113135 is a deficient number, since it is larger than the sum of its proper divisors (263267624561).
1304243113135 is an equidigital number, since it uses as much as digits as its factorization.
1304243113135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 403166993.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 1304243113135 its reverse (5313113424031), we get a palindrome (6617356537166).
The spelling of 1304243113135 in words is "one trillion, three hundred four billion, two hundred forty-three million, one hundred thirteen thousand, one hundred thirty-five".
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