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1304250107 is a prime number
BaseRepresentation
bin100110110111101…
…0100011011111011
310100220011202210112
41031233110123323
510132342000412
6333230334535
744214641306
oct11557243373
93326152715
101304250107
1160a240456
1230495a44b
1317a295634
14c5309b3d
157977e722
hex4dbd46fb

1304250107 has 2 divisors, whose sum is σ = 1304250108. Its totient is φ = 1304250106.

The previous prime is 1304250097. The next prime is 1304250109. The reversal of 1304250107 is 7010524031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1304250107 - 24 = 1304250091 is a prime.

It is a super-2 number, since 2×13042501072 = 3402136683219022898, which contains 22 as substring.

Together with 1304250109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1304250109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652125053 + 652125054.

It is an arithmetic number, because the mean of its divisors is an integer number (652125054).

Almost surely, 21304250107 is an apocalyptic number.

1304250107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304250107 is an equidigital number, since it uses as much as digits as its factorization.

1304250107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 1304250107 is about 36114.4030408921. The cubic root of 1304250107 is about 1092.5809576125.

Adding to 1304250107 its reverse (7010524031), we get a palindrome (8314774138).

The spelling of 1304250107 in words is "one billion, three hundred four million, two hundred fifty thousand, one hundred seven".