Base | Representation |
---|---|
bin | 11101101010000000101011… |
… | …110100011010001101001111 |
3 | 122002211000102000010221210211 |
4 | 131222000223310122031033 |
5 | 114043432224303112142 |
6 | 1141222504211143251 |
7 | 36321164321325553 |
oct | 3552005364321517 |
9 | 562730360127724 |
10 | 130430302004047 |
11 | 386171a9196781 |
12 | 127663242a4b27 |
13 | 57a16a8a08626 |
14 | 242cc08941863 |
15 | 1012bd1373917 |
hex | 76a02bd1a34f |
130430302004047 has 2 divisors, whose sum is σ = 130430302004048. Its totient is φ = 130430302004046.
The previous prime is 130430302004033. The next prime is 130430302004063. The reversal of 130430302004047 is 740400203034031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (740400203034031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130430302004047 - 211 = 130430302001999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130430302004087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215151002023 + 65215151002024.
It is an arithmetic number, because the mean of its divisors is an integer number (65215151002024).
Almost surely, 2130430302004047 is an apocalyptic number.
130430302004047 is a deficient number, since it is larger than the sum of its proper divisors (1).
130430302004047 is an equidigital number, since it uses as much as digits as its factorization.
130430302004047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 31.
Adding to 130430302004047 its reverse (740400203034031), we get a palindrome (870830505038078).
The spelling of 130430302004047 in words is "one hundred thirty trillion, four hundred thirty billion, three hundred two million, four thousand, forty-seven".
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