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130430302013111 = 5312371989449551
BaseRepresentation
bin11101101010000000101011…
…110100011100011010110111
3122002211000102000011102020112
4131222000223310130122313
5114043432224303404421
61141222504211253235
736321164321364152
oct3552005364343267
9562730360142215
10130430302013111
11386171a91a2571
12127663242aa21b
1357a16a8a0c7a9
14242cc08944c99
151012bd137645b
hex76a02bd1c6b7

130430302013111 has 8 divisors (see below), whose sum is σ = 132998681450304. Its totient is φ = 127865901477600.

The previous prime is 130430302013029. The next prime is 130430302013153. The reversal of 130430302013111 is 111310203034031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130430302013111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130430302013191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 994659215 + ... + 994790336.

It is an arithmetic number, because the mean of its divisors is an integer number (16624835181288).

Almost surely, 2130430302013111 is an apocalyptic number.

130430302013111 is a deficient number, since it is larger than the sum of its proper divisors (2568379437193).

130430302013111 is a wasteful number, since it uses less digits than its factorization.

130430302013111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1989450841.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 130430302013111 its reverse (111310203034031), we get a palindrome (241740505047142).

The spelling of 130430302013111 in words is "one hundred thirty trillion, four hundred thirty billion, three hundred two million, thirteen thousand, one hundred eleven".

Divisors: 1 53 1237 65561 1989449551 105440826203 2460949094587 130430302013111