13043302441 has 4 divisors (see below), whose sum is σ = 14046633412. Its totient is φ = 12039971472.

The previous prime is 13043302439. The next prime is 13043302453. The reversal of 13043302441 is 14420334031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1801153600 + 11242148841 = 42440^2 + 106029^2 .

It is a cyclic number.

It is not a de Polignac number, because 13043302441 - 2¹ = 13043302439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13043302541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501665466 + ... + 501665491.

It is an arithmetic number, because the mean of its divisors is an integer number (3511658353).

Almost surely, 2^13043302441 is an apocalyptic number.

It is an amenable number.

13043302441 is a deficient number, since it is larger than the sum of its proper divisors (1003330971).

13043302441 is a wasteful number, since it uses less digits than its factorization.

13043302441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1003330970.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13043302441 its reverse (14420334031), we get a palindrome (27463636472).

The spelling of 13043302441 in words is "thirteen billion, forty-three million, three hundred two thousand, four hundred forty-one".