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130433211420442 = 2788710503560269
BaseRepresentation
bin11101101010000011011001…
…001110111100111100011010
3122002211021220202201121210121
4131222003121032330330122
5114044004204110423232
61141224105022103454
736321326400055240
oct3552033116747432
9562737822647717
10130433211420442
1138618461507337
12127669b671ab8a
1357a1a506c53a8
14242d0030c8790
151012d019c2d97
hex76a0d93bcf1a

130433211420442 has 16 divisors (see below), whose sum is σ = 223851876474240. Its totient is φ = 55836926384688.

The previous prime is 130433211420433. The next prime is 130433211420451. The reversal of 130433211420442 is 244024112334031.

It is an interprime number because it is at equal distance from previous prime (130433211420433) and next prime (130433211420451).

It is a junction number, because it is equal to n+sod(n) for n = 130433211420398 and 130433211420407.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5251767717 + ... + 5251792552.

It is an arithmetic number, because the mean of its divisors is an integer number (13990742279640).

Almost surely, 2130433211420442 is an apocalyptic number.

130433211420442 is a deficient number, since it is larger than the sum of its proper divisors (93418665053798).

130433211420442 is a wasteful number, since it uses less digits than its factorization.

130433211420442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10503561165.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 130433211420442 its reverse (244024112334031), we get a palindrome (374457323754473).

The spelling of 130433211420442 in words is "one hundred thirty trillion, four hundred thirty-three billion, two hundred eleven million, four hundred twenty thousand, four hundred forty-two".

Divisors: 1 2 7 14 887 1774 6209 12418 10503560269 21007120538 73524921883 147049843766 9316657958603 18633315917206 65216605710221 130433211420442