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130433401230000 = 2435411395252731
BaseRepresentation
bin11101101010000011100100…
…100011000001001010110000
3122002211022101222212221120020
4131222003210203001022300
5114044010101203330000
61141224135522243440
736321334163321001
oct3552034443011260
9562738358787506
10130433401230000
113861854966a040
1212766a4a1b6580
1357a1a80b2223b
14242d0203b71a8
151012d134b7ba0
hex76a0e48c12b0

130433401230000 has 200 divisors, whose sum is σ = 459334266933696. Its totient is φ = 31620218400000.

The previous prime is 130433401229987. The next prime is 130433401230019. The reversal of 130433401230000 is 32104334031.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 197296366 + ... + 197956365.

Almost surely, 2130433401230000 is an apocalyptic number.

130433401230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130433401230000 is an abundant number, since it is smaller than the sum of its proper divisors (328900865703696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130433401230000 is a wasteful number, since it uses less digits than its factorization.

130433401230000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 395252773 (or 395252752 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 130433401230000 its reverse (32104334031), we get a palindrome (130465505564031).

The spelling of 130433401230000 in words is "one hundred thirty trillion, four hundred thirty-three billion, four hundred one million, two hundred thirty thousand".