13043411 has 2 divisors, whose sum is σ = 13043412. Its totient is φ = 13043410.

The previous prime is 13043399. The next prime is 13043431. The reversal of 13043411 is 11434031.

13043411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13043411 - 2¹⁸ = 12781267 is a prime.

It is a Chen prime.

It is a plaindrome in base 15.

It is a self number, because there is not a number n which added to its sum of digits gives 13043411.

It is not a weakly prime, because it can be changed into another prime (13043431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521705 + 6521706.

It is an arithmetic number, because the mean of its divisors is an integer number (6521706).

Almost surely, 2^13043411 is an apocalyptic number.

13043411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043411 is an equidigital number, since it uses as much as digits as its factorization.

13043411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 13043411 is about 3611.5662807153. The cubic root of 13043411 is about 235.3949056486.

Adding to 13043411 its reverse (11434031), we get a palindrome (24477442).

The spelling of 13043411 in words is "thirteen million, forty-three thousand, four hundred eleven".