130434120110113 has 4 divisors (see below), whose sum is σ = 130435563486868. Its totient is φ = 130432676733360.

The previous prime is 130434120110071. The next prime is 130434120110137. The reversal of 130434120110113 is 311011021434031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 54451308666769 + 75982811443344 = 7379113^2 + 8716812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130434120110113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130434120117113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 721552818 + ... + 721733563.

It is an arithmetic number, because the mean of its divisors is an integer number (32608890871717).

Almost surely, 2^{130434120110113} is an apocalyptic number.

It is an amenable number.

130434120110113 is a deficient number, since it is larger than the sum of its proper divisors (1443376755).

130434120110113 is an equidigital number, since it uses as much as digits as its factorization.

130434120110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1443376754.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 130434120110113 its reverse (311011021434031), we get a palindrome (441445141544144).

The spelling of 130434120110113 in words is "one hundred thirty trillion, four hundred thirty-four billion, one hundred twenty million, one hundred ten thousand, one hundred thirteen".