Base | Representation |
---|---|
bin | 1011110111001110100100… |
… | …1101110011100110100011 |
3 | 1201011221101022010221020211 |
4 | 2331303221031303212203 |
5 | 3202200422423434334 |
6 | 43424023125314551 |
7 | 2514233303524525 |
oct | 275635115634643 |
9 | 51157338127224 |
10 | 13043433421219 |
11 | 4179764140a33 |
12 | 1567aa3565a57 |
13 | 737cb5165a66 |
14 | 33143c5bda15 |
15 | 1794527c8a64 |
hex | bdce93739a3 |
13043433421219 has 2 divisors, whose sum is σ = 13043433421220. Its totient is φ = 13043433421218.
The previous prime is 13043433421157. The next prime is 13043433421241. The reversal of 13043433421219 is 91212433434031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13043433421219 is a prime.
It is a super-3 number, since 3×130434334212193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13043433428219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521716710609 + 6521716710610.
It is an arithmetic number, because the mean of its divisors is an integer number (6521716710610).
Almost surely, 213043433421219 is an apocalyptic number.
13043433421219 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043433421219 is an equidigital number, since it uses as much as digits as its factorization.
13043433421219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 40.
The spelling of 13043433421219 in words is "thirteen trillion, forty-three billion, four hundred thirty-three million, four hundred twenty-one thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •