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13043433421219 is a prime number
BaseRepresentation
bin1011110111001110100100…
…1101110011100110100011
31201011221101022010221020211
42331303221031303212203
53202200422423434334
643424023125314551
72514233303524525
oct275635115634643
951157338127224
1013043433421219
114179764140a33
121567aa3565a57
13737cb5165a66
1433143c5bda15
151794527c8a64
hexbdce93739a3

13043433421219 has 2 divisors, whose sum is σ = 13043433421220. Its totient is φ = 13043433421218.

The previous prime is 13043433421157. The next prime is 13043433421241. The reversal of 13043433421219 is 91212433434031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13043433421219 is a prime.

It is a super-3 number, since 3×130434334212193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13043433428219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521716710609 + 6521716710610.

It is an arithmetic number, because the mean of its divisors is an integer number (6521716710610).

Almost surely, 213043433421219 is an apocalyptic number.

13043433421219 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043433421219 is an equidigital number, since it uses as much as digits as its factorization.

13043433421219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 186624, while the sum is 40.

The spelling of 13043433421219 in words is "thirteen trillion, forty-three billion, four hundred thirty-three million, four hundred twenty-one thousand, two hundred nineteen".