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13043433421241 is a prime number
BaseRepresentation
bin1011110111001110100100…
…1101110011100110111001
31201011221101022010221021122
42331303221031303212321
53202200422423434431
643424023125315025
72514233303524556
oct275635115634671
951157338127248
1013043433421241
114179764140a53
121567aa3565a75
13737cb5165a82
1433143c5bda2d
151794527c8a7b
hexbdce93739b9

13043433421241 has 2 divisors, whose sum is σ = 13043433421242. Its totient is φ = 13043433421240.

The previous prime is 13043433421219. The next prime is 13043433421243. The reversal of 13043433421241 is 14212433434031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11993781945616 + 1049651475625 = 3463204^2 + 1024525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13043433421241 is a prime.

Together with 13043433421243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13043433421243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521716710620 + 6521716710621.

It is an arithmetic number, because the mean of its divisors is an integer number (6521716710621).

Almost surely, 213043433421241 is an apocalyptic number.

It is an amenable number.

13043433421241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043433421241 is an equidigital number, since it uses as much as digits as its factorization.

13043433421241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13043433421241 its reverse (14212433434031), we get a palindrome (27255866855272).

The spelling of 13043433421241 in words is "thirteen trillion, forty-three billion, four hundred thirty-three million, four hundred twenty-one thousand, two hundred forty-one".