Base | Representation |
---|---|
bin | 10010111110110000111… |
… | …110101110011111001000 |
3 | 11121200201222221222110112 |
4 | 102332300332232133020 |
5 | 132332244121332130 |
6 | 2435112453333452 |
7 | 163143603552212 |
oct | 22766076563710 |
9 | 4550658858415 |
10 | 1304344324040 |
11 | 46319540413a |
12 | 19095a337288 |
13 | 95ccb165694 |
14 | 471b852d5b2 |
15 | 23de0512495 |
hex | 12fb0fae7c8 |
1304344324040 has 32 divisors (see below), whose sum is σ = 2934842319360. Its totient is φ = 521725713600.
The previous prime is 1304344324027. The next prime is 1304344324079. The reversal of 1304344324040 is 404234434031.
It is a junction number, because it is equal to n+sod(n) for n = 1304344323988 and 1304344324006.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1498475 + ... + 2203205.
It is an arithmetic number, because the mean of its divisors is an integer number (91713822480).
Almost surely, 21304344324040 is an apocalyptic number.
1304344324040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1304344324040 is an abundant number, since it is smaller than the sum of its proper divisors (1630497995320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304344324040 is a wasteful number, since it uses less digits than its factorization.
1304344324040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 751013 (or 751009 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 1304344324040 its reverse (404234434031), we get a palindrome (1708578758071).
The spelling of 1304344324040 in words is "one trillion, three hundred four billion, three hundred forty-four million, three hundred twenty-four thousand, forty".
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