Base | Representation |
---|---|
bin | 10010111110110011110… |
… | …011100111100111010101 |
3 | 11121200212022012011100202 |
4 | 102332303303213213111 |
5 | 132332343241301312 |
6 | 2435121305550245 |
7 | 163145020612541 |
oct | 22766363474725 |
9 | 4550768164322 |
10 | 1304391743957 |
11 | 46320a152455 |
12 | 1909721a5385 |
13 | 96007c295c3 |
14 | 471c0954a21 |
15 | 23de477c9c2 |
hex | 12fb3ce79d5 |
1304391743957 has 2 divisors, whose sum is σ = 1304391743958. Its totient is φ = 1304391743956.
The previous prime is 1304391743947. The next prime is 1304391743959. The reversal of 1304391743957 is 7593471934031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1169586012676 + 134805731281 = 1081474^2 + 367159^2 .
It is an emirp because it is prime and its reverse (7593471934031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304391743957 - 222 = 1304387549653 is a prime.
Together with 1304391743959, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304391743959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652195871978 + 652195871979.
It is an arithmetic number, because the mean of its divisors is an integer number (652195871979).
Almost surely, 21304391743957 is an apocalyptic number.
It is an amenable number.
1304391743957 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304391743957 is an equidigital number, since it uses as much as digits as its factorization.
1304391743957 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8573040, while the sum is 56.
The spelling of 1304391743957 in words is "one trillion, three hundred four billion, three hundred ninety-one million, seven hundred forty-three thousand, nine hundred fifty-seven".
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