13044000000040 has 16 divisors (see below), whose sum is σ = 29349000000180. Its totient is φ = 5217600000000.

The previous prime is 13043999999969. The next prime is 13044000000049. The reversal of 13044000000040 is 4000000044031.

It can be written as a sum of positive squares in 2 ways, for example, as 12193351642404 + 850648357636 = 3491898^2 + 922306^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13043999999960 and 13044000000023.

It is not an unprimeable number, because it can be changed into a prime (13044000000049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163049999961 + ... + 163050000040.

Almost surely, 2^{13044000000040} is an apocalyptic number.

13044000000040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13044000000040 is an abundant number, since it is smaller than the sum of its proper divisors (16305000000140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044000000040 is a wasteful number, since it uses less digits than its factorization.

13044000000040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 326100000012 (or 326100000008 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 16.

Adding to 13044000000040 its reverse (4000000044031), we get a palindrome (17044000044071).

The spelling of 13044000000040 in words is "thirteen trillion, forty-four billion, forty", and thus it is an aban number.