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13044000014340 = 223517929340110337
BaseRepresentation
bin1011110111010000101011…
…1111001100000000000100
31201011222211210021211220020
42331310022333030000010
53202203103000424330
643424155245335140
72514253323505521
oct275641277140004
951158753254806
1013044000014340
114179a24a51809
1215680212674b0
13738075665a69
1433149394c148
151794873e8210
hexbdd0afcc004

13044000014340 has 192 divisors, whose sum is σ = 36948064930560. Its totient is φ = 3438233190400.

The previous prime is 13044000014329. The next prime is 13044000014363. The reversal of 13044000014340 is 4341000044031.

It is a self number, because there is not a number n which added to its sum of digits gives 13044000014340.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1261869652 + ... + 1261879988.

It is an arithmetic number, because the mean of its divisors is an integer number (192437838180).

Almost surely, 213044000014340 is an apocalyptic number.

13044000014340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13044000014340 is an abundant number, since it is smaller than the sum of its proper divisors (23904064916220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044000014340 is a wasteful number, since it uses less digits than its factorization.

13044000014340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11222 (or 11220 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13044000014340 its reverse (4341000044031), we get a palindrome (17385000058371).

The spelling of 13044000014340 in words is "thirteen trillion, forty-four billion, fourteen thousand, three hundred forty".