13044000043031 has 4 divisors (see below), whose sum is σ = 13045073017272. Its totient is φ = 13042927068792.

The previous prime is 13044000042971. The next prime is 13044000043079. The reversal of 13044000043031 is 13034000044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13044000043031 - 2³⁸ = 12769122136087 is a prime.

It is a super-2 number, since 2×13044000043031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044000042988 and 13044000043006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044000043091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 536468885 + ... + 536493198.

It is an arithmetic number, because the mean of its divisors is an integer number (3261268254318).

Almost surely, 2^{13044000043031} is an apocalyptic number.

13044000043031 is a deficient number, since it is larger than the sum of its proper divisors (1072974241).

13044000043031 is a wasteful number, since it uses less digits than its factorization.

13044000043031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1072974240.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13044000043031 its reverse (13034000044031), we get a palindrome (26078000087062).

The spelling of 13044000043031 in words is "thirteen trillion, forty-four billion, forty-three thousand, thirty-one".