13044001040231 has 4 divisors (see below), whose sum is σ = 14907429760272. Its totient is φ = 11180572320192.

The previous prime is 13044001040227. The next prime is 13044001040267. The reversal of 13044001040231 is 13204010044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13044001040231 - 2² = 13044001040227 is a prime.

It is a super-2 number, since 2×13044001040231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044001040197 and 13044001040206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044001040221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 931714360010 + ... + 931714360023.

It is an arithmetic number, because the mean of its divisors is an integer number (3726857440068).

Almost surely, 2^{13044001040231} is an apocalyptic number.

13044001040231 is a deficient number, since it is larger than the sum of its proper divisors (1863428720041).

13044001040231 is an equidigital number, since it uses as much as digits as its factorization.

13044001040231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1863428720040.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13044001040231 its reverse (13204010044031), we get a palindrome (26248011084262).

The spelling of 13044001040231 in words is "thirteen trillion, forty-four billion, one million, forty thousand, two hundred thirty-one".