Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100010000011011110010000 |
3 | 122002211221110122201020022202 |
4 | 131222021232202003132100 |
5 | 114044112120331403100 |
6 | 1141231151445022332 |
7 | 36321660035202506 |
oct | 3552115642033620 |
9 | 562757418636282 |
10 | 130440011200400 |
11 | 386203308386a0 |
12 | 127681939b49a8 |
13 | 57a2595397b25 |
14 | 242d48a206676 |
15 | 101309d93c7d5 |
hex | 76a26e883790 |
130440011200400 has 240 divisors, whose sum is σ = 363466256849280. Its totient is φ = 44514390835200.
The previous prime is 130440011200393. The next prime is 130440011200493. The reversal of 130440011200400 is 4002110044031.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6796145 + ... + 17523344.
It is an arithmetic number, because the mean of its divisors is an integer number (1514442736872).
Almost surely, 2130440011200400 is an apocalyptic number.
130440011200400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130440011200400 is an abundant number, since it is smaller than the sum of its proper divisors (233026245648880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130440011200400 is a wasteful number, since it uses less digits than its factorization.
130440011200400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24319594 (or 24319583 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 130440011200400 its reverse (4002110044031), we get a palindrome (134442121244431).
The spelling of 130440011200400 in words is "one hundred thirty trillion, four hundred forty billion, eleven million, two hundred thousand, four hundred".
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