1304400112241 has 2 divisors, whose sum is σ = 1304400112242. Its totient is φ = 1304400112240.

The previous prime is 1304400112229. The next prime is 1304400112243. The reversal of 1304400112241 is 1422110044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 721643454016 + 582756658225 = 849496^2 + 763385^2 .

It is an emirp because it is prime and its reverse (1422110044031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304400112241 - 2³⁰ = 1303326370417 is a prime.

Together with 1304400112243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1304400112243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652200056120 + 652200056121.

It is an arithmetic number, because the mean of its divisors is an integer number (652200056121).

Almost surely, 2^{1304400112241} is an apocalyptic number.

It is an amenable number.

1304400112241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304400112241 is an equidigital number, since it uses as much as digits as its factorization.

1304400112241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1304400112241 its reverse (1422110044031), we get a palindrome (2726510156272).

The spelling of 1304400112241 in words is "one trillion, three hundred four billion, four hundred million, one hundred twelve thousand, two hundred forty-one".