Base | Representation |
---|---|
bin | 1011110111010000101100… |
… | …0011101101110011111011 |
3 | 1201011222211212112011020112 |
4 | 2331310023003231303323 |
5 | 3202203103301421103 |
6 | 43424155331014535 |
7 | 2514253336551404 |
oct | 275641303556373 |
9 | 51158755464215 |
10 | 13044001201403 |
11 | 4179a25692657 |
12 | 156802173a44b |
13 | 738075990173 |
14 | 331493b7a9ab |
15 | 17948757ecd8 |
hex | bdd0b0edcfb |
13044001201403 has 8 divisors (see below), whose sum is σ = 13112921688048. Its totient is φ = 12975259497984.
The previous prime is 13044001201397. The next prime is 13044001201421. The reversal of 13044001201403 is 30410210044031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13044001201403 - 222 = 13043997007099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13044001201453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44549501 + ... + 44841342.
It is an arithmetic number, because the mean of its divisors is an integer number (1639115211006).
Almost surely, 213044001201403 is an apocalyptic number.
13044001201403 is a deficient number, since it is larger than the sum of its proper divisors (68920486645).
13044001201403 is an equidigital number, since it uses as much as digits as its factorization.
13044001201403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89391613.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13044001201403 its reverse (30410210044031), we get a palindrome (43454211245434).
The spelling of 13044001201403 in words is "thirteen trillion, forty-four billion, one million, two hundred one thousand, four hundred three".
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