Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100101001100000101000111 |
3 | 122002211221110201020222110121 |
4 | 131222021232211030011013 |
5 | 114044112121034201322 |
6 | 1141231151514402411 |
7 | 36321660045164215 |
oct | 3552115645140507 |
9 | 562757421228417 |
10 | 130440012022087 |
11 | 38620331249a79 |
12 | 12768194130407 |
13 | 57a25955c4b31 |
14 | 242d48a37bcb5 |
15 | 101309da50ec7 |
hex | 76a26e94c147 |
130440012022087 has 2 divisors, whose sum is σ = 130440012022088. Its totient is φ = 130440012022086.
The previous prime is 130440012022079. The next prime is 130440012022091. The reversal of 130440012022087 is 780220210044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440012022087 - 23 = 130440012022079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130440012022057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006011043 + 65220006011044.
It is an arithmetic number, because the mean of its divisors is an integer number (65220006011044).
Almost surely, 2130440012022087 is an apocalyptic number.
130440012022087 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440012022087 is an equidigital number, since it uses as much as digits as its factorization.
130440012022087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 34.
The spelling of 130440012022087 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, twenty-two thousand, eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •